常规解法：
class ParkingSystem {
public:
ParkingSystem(int big, int medium, int small) {
this->big = big;
this->medium = medium;
this->small = small;
}
bool addCar(int carType) {
switch(carType)
{
case 1:
if(big > 0){big--;return true;}else return false;break;
case 2:
if(medium > 0){medium--;return true;}else return false;break;
case 3:
if(small > 0){small--;return true;}else return false;break;
}
return false;
}
private:
int big;
int medium;
int small;
};
/**
* Your ParkingSystem object will be instantiated and called as such:
* ParkingSystem* obj = new ParkingSystem(big, medium, small);
* bool param_1 = obj->addCar(carType);
*/上面的代码非常啰嗦，看了讨论区大神的代码，非常精简：
class ParkingSystem {
public:
ParkingSystem(int big, int medium, int small) {
count = {big,medium,small};
}
bool addCar(int carType) {
return count[carType - 1]-- > 0;
}
private:
vector<int> count;
};
/**
* Your ParkingSystem object will be instantiated and called as such:
* ParkingSystem* obj = new ParkingSystem(big, medium, small);
* bool param_1 = obj->addCar(carType);
*/上面的解法直接通过数组初始化vector，然后根据下标判断对应类型值是否大于0即可。